Question: (3x - 5) 2 (x +5) dx = Ax4 + Bx3 + Cx + Dx + E where A, B, C, D and E are

(3x - 5) 2 (x +5) dx = Ax4 + Bx3+ Cx + Dx + E where A, B, C, D andE are constants. What is the value of B + D

(3x - 5) 2 (x +5) dx = Ax4 + Bx3 + Cx + Dx + E where A, B, C, D and E are constants. What is the value of B + D

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