Question: Ffffff Slide 1 2 DEFINITION 1 2 . 1 A public - key encryption scheme is a triple of proba - bilistic polynomial - time

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Slide 12
DEFINITION 12.1
A public-key encryption scheme is a triple of proba-
bilistic polynomial-time algorithms (Gen, Enc, Dec) such that:
The key-generation algorithm Gen takes as input the security parameter
1" and outputs a pair of keys (pk, sk). We refer to the first of these as the public key and the second as the private key. We assume for convenience that ph and sk each has length at least n, and that n can be determined from ph, ski.
The public key pli defines a message space Mpk.
The encryption algorithm Enc takes as input a public key ph and message mE Mpk, and outputs a ciphertext c; we denote this by c + EnCpk(m).
(Looking ahead, Enc will need to be probabilistic in order to achieve meaningful security.)
The deterministic decryption algorithm Dec takes as input a private key ski and a ciphertext c, and outputs a message m or a special symbol 1 denoting failure. We write this as m:= Decsk (c).
Slide 14
The eavesdropping indistinguishability experiment PubKA,(n):
Gen(1) is run to obtain keys (pk, sh).
Adversary A is given pl, and outputs a pair of equal-length messages mo, m1 Mpk.
A uniform bit b e {0,1} is chosen, and then a ciphertext c+ EnCpk(mb) is computed and given to A. We call c the challenge ciphertext.
A outputs a bit b'. The output of the experiment is 1 if b'= b,
and 0 otherwise. If b'=6 we say that A succeeds.
DEFINITION 12.2 A public-key encryption scheme II =(Gen, Enc, Dec)
has indistinguishable encryptions in the presence of an eavesdropper if for all probabilistic polynomial-time adversaries A there is a negligible function negl such that
Pr|PubKAn(n)=1|<=
=+ negl(n).
Question 1.
[S] Definition 12.1 of a public-key encryption scheme (slide 12 of module 12.1) asserts in its item 2 that Enc will need to be
probabilistic in order to achieve meaningful security. Consider the eavesdropping indistinguishability experiment in slide
14 of module 12.1. Explain how the adversary will succeed with 100% probability if Enc is deterministic, so that in step 3 of
slide 14 we have c := Encpk(mb).
Question 2
[S] Assume that Enc in Definition 12.1 is indeed probabilistic. Suppose the randomization is O(n2) where n is the security
parameter. Explain how a PPT adversary in the experiment of slide 14 of module 12.1 will succeed in polynomial time.
Assume the adversary knows the randomization scheme used in Enc.
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