Question: fFormula's a3 + 63 = (a + b) (a2 - ab + 62 a3 - 63 = ( a - b) a + ab +

 \fFormula's a3 + 63 = (a + b) (a2 - ab+ 62 a3 - 63 = ( a - b) a +

\fFormula's a3 + 63 = (a + b) (a2 - ab + 62 a3 - 63 = ( a - b) a + ab + 62 -btv 62 -4ac = 2a

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