\fGiven that: Let X 8 and 5 is normally distributed. a) The percent of the fish longer than 11 inches is, P X 11 1 P Z 11 11 8 1 P Z 5 1 P Z 0.6 From Standard normal tables 1 0.725747 0.274253 Rounding 4 decimal place 0.2743 27.43% Hence, the required percent is: 27.43% b) If 300 fish are randomly selected, about how many you expect to be shorter tha 7 inches is, Here, n 300 P X 7 P Z 7 7 8 P Z 5 P Z 0.2 0.42074 0.4207 From Standard normal tables Rounding 4 decimal place The required fishes is, 300 0.4207 126.21 126 Hence, you would expect approximately 126 fish to be shorter than 7 inches