\fGroup #3 Problems use these sets of problems if your last name begins with P 2. in your subject line on the post use: Group #3 The rst clue to solving the crime is following the trash! This lunch stealer Is also a lltterbug and left a trail. Following the sandwich bag, the chip bag, the candy wrapper, and the soda can has led me to one particular building on campus. Find out which one using the problems from Set #1. Set #1: Find the vertex for each of the following parabolas. 1Iilirlte your answer as an ordered pair. f{x1=r2+x+l ffx}=2x2+3x Match each of your four answers to the ordered pairs provided for cfue #1 in the last chart on page 2. You eliminate a building for each answer that you match. If your answer does not appear in the list. you have made an error and should re-worir that problem. One building will remain in the st and that is the building which houses the thief. Now move to the second clue. The second clue to solving the crime is following the crumbs! This mlscreant is also a messy eater and has left a hall of crumbs at the door of the bulldlng. Follow these crumbs to find out which oor of the building the crimlnal is on. Set #2: Determine the real zeros of each polynomial and what the behavior of the function at that zero would be. either it crosses through the zero or touches and turns around. Match each of your four answers to the mere: and behavior provided for ctue #2 in the last chart on page 2. 'fou eliminate a floor for each answer that you match. if your answer does not appear in the list. you have made an error and should re-worl: that problem. One floor will remain in the list and that is the ner where the thief is. Now move to the third clue. The third clue to solving the crime Is a chocolate smudge! This lawless toad doesn't wash their hands and has left chocolate proof of their ltllevery on their very own ofce doorl Use these problems to nd their office. Set #3: Determine the Horicontal Asymptote for each rational function f[x}=4xz x2+Tx Tx' +9 fix]: x3+5x Match each of your fouranswers to the horizontal asymptotes provided for clue #3 in the last chart on page 2. 1I'ou eliminate an ofce for each answer that you match. If your answer does not appear in the list, you have made an error and shoutd re-worlr that problem. One ofce will remain in the list and that is the ofce of the thief. Now move to the fourth and nal clue. . Group # 3 Mo Set # 1 _ x 2 + 8 x F ( * ) = * 2 + * + 1 f ( ) = x 2 6 x+ 9 8 Ffx ) = 2x2 +3x 2(-1 ) - 6 124 (4 , 16 ) 3 2 (1 ) 2( 1 1 2(2) - 4 + 8 (41 *= - / X= 3 *= - 9 f ( * ) = 32 - 6 (3 ) + 9 21- 3, 4) 2+ 31-3/4) Martin Oswalt = 0 ClassROOM Set # 2 3 , 0 - -4/8 Moloney PCE) = ( 4 - 2 ) Call ? 4 ( x- 3) 5 (x+2) / (x- 312 ( x +2) 4 -2x6 (x-1 )5 4- 35 20 K23 (X - 3 ) 20 * 2 3 * = B X - 2 20 (x- 11 20 / x+2 = 0 *2 - 2 Cross 3 Tams 3 *= 2 Cross - 2 Crosses 1 Turns Turns O 15 + flour floor and floor Crosses with floor set # 3 14 - 3 x5 x1 - 6x 9 12 - 6 7+2 + 9 42 0 45 + 1 E yz -3 B NONe Set # y A + 2 D 1- 3 x2 - 10 * = 3 X- 4 X 2 0