Question: Fig. 1 . Direct Form I filter aH ( e ^ ( j omega ) ) = ( Y ( e ^ ( j

Fig. 1. Direct Form I filter
aH(e^(j\omega ))=(Y(e^(j\omega )))/(x(e^(j\omega )))=(\sum_(m=0)^M b_(m)e^(-j\omega m))/(1+\sum_(k=1)^N a_(k)e^(-j\omega k)).
Using the values of coefficients on the filter
diagram, find the poles and zeros of the filter
and plot them on the diagram below.
cH(z) for the system.
dh[n] as the inverse z-trensform
of H(z). Fig. 1. Direct Form I filter
aH(e^(j\omega ))=(Y(e^(j\omega )))/(x(e^(j\omega )))=(\sum_(m=0)^M b_(m)e^(-j\omega m))/(1+\sum_(k=1)^N a_(k)e^(-j\omega k)).
Using the values of coefficients on the filter
diagram, find the poles and zeros of the filter
and plot them on the diagram below.
cH(z) for the system.
dh[n] as the inverse z-trensform
of H(z). e) State whether the filter is stable or unstable and why.
f) If just one of the coefficients of the filter (hie one of '\( a \)' or '\( b \)' values) is changed to the negative of its stated value, can the filter be made unstable? If so, state why. If not, state why not.
Fig. 1 . Direct Form I filter aH ( e ^ ( j \

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