Fig.Q$.1$

Material:C$20$

Cross$-$Section:$25/60($Beam$)$

$a=5$

$b=2$

$L=6+a[m]$

$L_1=\frac{L}{a+b}[m]$

$L_2=\frac{L}{b}[m]$

$P=(10+a)b[kN]$

${}_C=$

Solve this problem step by step and give me the final result