Question: Figure 1 shows the plan view of a rectangular slab supported on four pinned edges , BD and CD ) . The moment capacity is

Figure 1 shows the plan view of a rectangular slab supported on four pinned edges , BD and CD ). The moment capacity is mkNmm in all directions (i.e., the slab is isotropic). Using yield line theory, you are required to find the minimum uniformly distributed load w(kNm2) acting perpendicular to the plan view, which will make the slab collapse.
Note: Values of L1,L2, and m are different for each student and provided in Table 1.
Hint: The actual direction of the yield line is initially unknown, i.e., it depends on the unknown value of the variable x represented in Figure 1. To solve this problem you need to recall that the yield line method is an upper bound method, i.e., the solution will be exact if the yield line pattern is chosen accurately, or the estimated solution will be actually higher than the exact solution (and as result, an unsafe and non-conservative estimation) if the yield line pattern is not chosen properly. You have a couple of alternative options to reach your solution (you do not need to do both alternatives, one of them is sufficient to achieve full marks):
Option (i): Pick a hypothetical point at a distance x(as in Figure 1) that three of the yield lines will go through. Then, make all internal work and external work a function of the coordinate x of this hypothetical point assumed to be an end point of three of the yield lines. Ultimately, calculate the collapse load wcollapse as a function of x, and make the derivative of the collapse load wcollapse with respect to x equal to zero to obtain the x that will give you the minimum value of wcollapse. Once you have obtained x that will minimize wcollapse, you can obtain the exact wcollapse.
Option (ii): Alternatively, you can calculate the numerical value of the collapse load (
Figure 1 shows the plan view of a rectangular

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