Figure 3b -0 Figure 3a A photograph and as diagram of the apparatus we used...

  

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Figure 3b -0 ㅏ Figure 3a A photograph and as diagram of the apparatus we used in Lab 10 shown above. In this apparatus a string can be wound around any of four different hubs and atta Page 492 hanging mass at the other end. When the hanging mass falls from rest it will cause the apparatus to accelerate. Note: The diameters of the four hubs are 4.50 cm, 6.00 cm, 7.50 cm and 9.00 cm. the mass of rotating disk mo is 700 g. The hanging mass (mh) is 150 g. The length of each of the four rods (LR) is 30.0 cm. The mass of each rod is (mr) are 74.0 g. The cylinder masses are 4.00 cm in diameter, 2.00 cm thick, and have a mass (m) of 185 g. The apparatus is constructed so the two cylinder masses are attached to the bar at their nearest positions which is a distance of R₁ = 6.00 cm from the axis to the center of the mass. They are opposite each other for balance. The other two cylinder masses are attached to the bar at their farthest positions which is a distance of R$ = 34.00 cm from the axis to the center of the mass. (b) The maximum angular velocity of the apparatus. Wmax = 3.50 (c) The distance that the hanging mass falls. Ay = 0.05 -0 With the string wrapped around the smallest hub and the hanging mass just barely touching the table, the apparatus is wound through exactly 2.00 rotations. Thus when the hanging mass is released from rest, the apparatus will rotate through 2.00 rotations before the hanging mass hits the table When the apparatus is released from rest, it take 7.17 s for the hanging mass to touch the table. Find the following quantities. (a) The angular acceleration of the apparatus. a = 0.49 rad/s² cm rad/s (d) The velocity of the hanging mass as it strikes the table. Uf = 71.7 (e) The angular velocity of the inner masses when the hanging mass touched the floor. cyl = 12.63 x rad/s x cm/s Group 1 - Definitions (1.1) 400f-Oi f-0₂ (1.2) (1.3) ū = (1.4) α = 48 At Δω At 0f-0₂ At - (2.2) Δθ = 48. do =lim At = dt (2.3) 40=w₂t+1 at² →04t Group 2 - Derived - Calculate (2.1) wf =W₂ +at 2 wf-Wz At wftwit 2 (2.4) w ²/= w²+2x40 +2α Δθ (1.5) x = lim Au-du- d20 (2.5) = Δω = w At dt dt² w f t W; 2 Group 3 - Conversions (3.1) Sr.0 (3.2) Ut=r.w (3.3) at = r.a (3.4) ac = v² = w2r Figure 3b -0 ㅏ Figure 3a A photograph and as diagram of the apparatus we used in Lab 10 shown above. In this apparatus a string can be wound around any of four different hubs and attad Page 492 hanging mass at the other end. When the hanging mass falls from rest it will cause the apparatus to accelerate. Note: The diameters of the four hubs are 4.50 cm, 6.00 cm, 7.50 cm and 9.00 cm. the mass of rotating disk mp is 700 g. The hanging mass (mn) is 150 g. The length of each of the four rods (LR) is 30.0 cm. The mass of each rod is (mg) are 74.0 g. The cylinder masses are 4.00 cm in diameter, 2.00 cm thick, and have a mass (m) of 185 g. The apparatus is constructed so the two cylinder masses are attached to the bar at their nearest positions which is a distance of R₁ = 6.00 cm from the axis to the center of the mass. They are opposite each other for balance. The other two cylinder masses are attached to the bar at their farthest positions which is a distance of R$ = 34.00 cm from the axis to the center of the mass. (b) The maximum angular velocity of the apparatus. Wmax = 3.50 (c) The distance that the hanging mass falls. Ay = 0.05 -0 With the string wrapped around the smallest hub and the hanging mass just barely touching the table, the apparatus is wound through exactly 2.00 rotations. Thus when the hanging mass is released from rest, the apparatus will rotate through 2.00 rotations before the hanging mass hits the table When the apparatus is released from rest, it take 7.17 s for the hanging mass to touch the table. Find the following quantities. (a) The angular acceleration of the apparatus. Q = 0.49 rad/s² cm rad/s (d) The velocity of the hanging mass as it strikes the table. Uf = 71.7 (e) The angular velocity of the inner masses when the hanging mass touched the floor. cyl = 12.63 x rad/s x cm/s Group 1 Definitions (1.1) 400f-Oi 40=0f-0₂ (1.2) (1.3) ū = (1.4) α = 48 At - Δω At 2 0f-0₂ At Group 2 - Derived - Calculate (2.1) wf =W₂ +at 2 wf-Wz At (2.2) Δθ = 48. do =lim At = dt (2.3) 40=w₂t+at² 04t wftwit 2 (2.4) W²/= w²+2x40 +2α Δθ (1.5) x = lim Au-du-d20 (2.5) = Δω = w At dt dt² w f t W; 2 Group 3 - Conversions (3.1) ST.0 (3.2) Ut=r.w (3.3) ar.a (3.4) ac = v² = w2r Figure 3b -0 ㅏ Figure 3a A photograph and as diagram of the apparatus we used in Lab 10 shown above. In this apparatus a string can be wound around any of four different hubs and attad Page 492 hanging mass at the other end. When the hanging mass falls from rest it will cause the apparatus to accelerate. Note: The diameters of the four hubs are 4.50 cm, 6.00 cm, 7.50 cm and 9.00 cm. the mass of rotating disk mo is 700 g. The hanging mass (mh) is 150 g. The length of each of the four rods (LR) is 30.0 cm. The mass of each rod is (mg) are 74.0 g. The cylinder masses are 4.00 cm in diameter, 2.00 cm thick, and have a mass (mc) of 185 g. The apparatus is constructed so the two cylinder masses are attached to the bar at their nearest positions which is a distance of R₁ = 6.00 cm from the axis to the center of the mass. They are opposite each other for balance. The other two cylinder masses are attached to the bar at their farthest positions which is a distance of R+ = 34.00 cm from the axis to the center of the mass. (b) The maximum angular velocity of the apparatus. Wmax = 3.50 (c) The distance that the hanging mass falls. Ay = 0.05 -0 With the string wrapped around the smallest hub and the hanging mass just barely touching the table, the apparatus is wound through exactly 2.00 rotations. Thus when the hanging mass is released from rest, the apparatus will rotate through 2.00 rotations before the hanging mass hits the table When the apparatus is released from rest, it take 7.17 s for the hanging mass to touch the table. Find the following quantities. (a) The angular acceleration of the apparatus. a = 0.49 rad/s² cm rad/s (d) The velocity of the hanging mass as it strikes the table. Uf = 71.7 (e) The angular velocity of the inner masses when the hanging mass touched the floor. Wcyl = 12.63 x rad/s x cm/s Group 1 Definitions (1.1) 400f-Oi 40=0f-0₂ (1.2) ū = 48 At (1.4) α = - 2 Δω At 0f-0₂ At (1.3) w 48. Group 2 - Derived - Calculate (2.1) W f =W₂ +at do =lim At=dt (2.3) 40=w₂t+1/at² 04t 2 wf-Wz At (2.2) Δθ = wftwit 2 (2.4) w ²/= w²+2x40 +2α Δθ (1.5) x = lim Au du = d20 (2.5) = Δω 1 w At dt dt² w f t W; 2 Group 3 - Conversions (3.1) Sr.0 (3.2) Ut=r.w (3.3) ar.a (3.4) ac = v² = w2r Figure 3b -0 ㅏ Figure 3a A photograph and as diagram of the apparatus we used in Lab 10 shown above. In this apparatus a string can be wound around any of four different hubs and atta Page 492 hanging mass at the other end. When the hanging mass falls from rest it will cause the apparatus to accelerate. Note: The diameters of the four hubs are 4.50 cm, 6.00 cm, 7.50 cm and 9.00 cm. the mass of rotating disk mo is 700 g. The hanging mass (mh) is 150 g. The length of each of the four rods (LR) is 30.0 cm. The mass of each rod is (mr) are 74.0 g. The cylinder masses are 4.00 cm in diameter, 2.00 cm thick, and have a mass (m) of 185 g. The apparatus is constructed so the two cylinder masses are attached to the bar at their nearest positions which is a distance of R₁ = 6.00 cm from the axis to the center of the mass. They are opposite each other for balance. The other two cylinder masses are attached to the bar at their farthest positions which is a distance of R$ = 34.00 cm from the axis to the center of the mass. (b) The maximum angular velocity of the apparatus. Wmax = 3.50 (c) The distance that the hanging mass falls. Ay = 0.05 -0 With the string wrapped around the smallest hub and the hanging mass just barely touching the table, the apparatus is wound through exactly 2.00 rotations. Thus when the hanging mass is released from rest, the apparatus will rotate through 2.00 rotations before the hanging mass hits the table When the apparatus is released from rest, it take 7.17 s for the hanging mass to touch the table. Find the following quantities. (a) The angular acceleration of the apparatus. a = 0.49 rad/s² cm rad/s (d) The velocity of the hanging mass as it strikes the table. Uf = 71.7 (e) The angular velocity of the inner masses when the hanging mass touched the floor. cyl = 12.63 x rad/s x cm/s Group 1 - Definitions (1.1) 400f-Oi f-0₂ (1.2) (1.3) ū = (1.4) α = 48 At Δω At 0f-0₂ At - (2.2) Δθ = 48. do =lim At = dt (2.3) 40=w₂t+1 at² →04t Group 2 - Derived - Calculate (2.1) wf =W₂ +at 2 wf-Wz At wftwit 2 (2.4) w ²/= w²+2x40 +2α Δθ (1.5) x = lim Au-du- d20 (2.5) = Δω = w At dt dt² w f t W; 2 Group 3 - Conversions (3.1) Sr.0 (3.2) Ut=r.w (3.3) at = r.a (3.4) ac = v² = w2r Figure 3b -0 ㅏ Figure 3a A photograph and as diagram of the apparatus we used in Lab 10 shown above. In this apparatus a string can be wound around any of four different hubs and attad Page 492 hanging mass at the other end. When the hanging mass falls from rest it will cause the apparatus to accelerate. Note: The diameters of the four hubs are 4.50 cm, 6.00 cm, 7.50 cm and 9.00 cm. the mass of rotating disk mp is 700 g. The hanging mass (mn) is 150 g. The length of each of the four rods (LR) is 30.0 cm. The mass of each rod is (mg) are 74.0 g. The cylinder masses are 4.00 cm in diameter, 2.00 cm thick, and have a mass (m) of 185 g. The apparatus is constructed so the two cylinder masses are attached to the bar at their nearest positions which is a distance of R₁ = 6.00 cm from the axis to the center of the mass. They are opposite each other for balance. The other two cylinder masses are attached to the bar at their farthest positions which is a distance of R$ = 34.00 cm from the axis to the center of the mass. (b) The maximum angular velocity of the apparatus. Wmax = 3.50 (c) The distance that the hanging mass falls. Ay = 0.05 -0 With the string wrapped around the smallest hub and the hanging mass just barely touching the table, the apparatus is wound through exactly 2.00 rotations. Thus when the hanging mass is released from rest, the apparatus will rotate through 2.00 rotations before the hanging mass hits the table When the apparatus is released from rest, it take 7.17 s for the hanging mass to touch the table. Find the following quantities. (a) The angular acceleration of the apparatus. Q = 0.49 rad/s² cm rad/s (d) The velocity of the hanging mass as it strikes the table. Uf = 71.7 (e) The angular velocity of the inner masses when the hanging mass touched the floor. cyl = 12.63 x rad/s x cm/s Group 1 Definitions (1.1) 400f-Oi 40=0f-0₂ (1.2) (1.3) ū = (1.4) α = 48 At - Δω At 2 0f-0₂ At Group 2 - Derived - Calculate (2.1) wf =W₂ +at 2 wf-Wz At (2.2) Δθ = 48. do =lim At = dt (2.3) 40=w₂t+at² 04t wftwit 2 (2.4) W²/= w²+2x40 +2α Δθ (1.5) x = lim Au-du-d20 (2.5) = Δω = w At dt dt² w f t W; 2 Group 3 - Conversions (3.1) ST.0 (3.2) Ut=r.w (3.3) ar.a (3.4) ac = v² = w2r Figure 3b -0 ㅏ Figure 3a A photograph and as diagram of the apparatus we used in Lab 10 shown above. In this apparatus a string can be wound around any of four different hubs and attad Page 492 hanging mass at the other end. When the hanging mass falls from rest it will cause the apparatus to accelerate. Note: The diameters of the four hubs are 4.50 cm, 6.00 cm, 7.50 cm and 9.00 cm. the mass of rotating disk mo is 700 g. The hanging mass (mh) is 150 g. The length of each of the four rods (LR) is 30.0 cm. The mass of each rod is (mg) are 74.0 g. The cylinder masses are 4.00 cm in diameter, 2.00 cm thick, and have a mass (mc) of 185 g. The apparatus is constructed so the two cylinder masses are attached to the bar at their nearest positions which is a distance of R₁ = 6.00 cm from the axis to the center of the mass. They are opposite each other for balance. The other two cylinder masses are attached to the bar at their farthest positions which is a distance of R+ = 34.00 cm from the axis to the center of the mass. (b) The maximum angular velocity of the apparatus. Wmax = 3.50 (c) The distance that the hanging mass falls. Ay = 0.05 -0 With the string wrapped around the smallest hub and the hanging mass just barely touching the table, the apparatus is wound through exactly 2.00 rotations. Thus when the hanging mass is released from rest, the apparatus will rotate through 2.00 rotations before the hanging mass hits the table When the apparatus is released from rest, it take 7.17 s for the hanging mass to touch the table. Find the following quantities. (a) The angular acceleration of the apparatus. a = 0.49 rad/s² cm rad/s (d) The velocity of the hanging mass as it strikes the table. Uf = 71.7 (e) The angular velocity of the inner masses when the hanging mass touched the floor. Wcyl = 12.63 x rad/s x cm/s Group 1 Definitions (1.1) 400f-Oi 40=0f-0₂ (1.2) ū = 48 At (1.4) α = - 2 Δω At 0f-0₂ At (1.3) w 48. Group 2 - Derived - Calculate (2.1) W f =W₂ +at do =lim At=dt (2.3) 40=w₂t+1/at² 04t 2 wf-Wz At (2.2) Δθ = wftwit 2 (2.4) w ²/= w²+2x40 +2α Δθ (1.5) x = lim Au du = d20 (2.5) = Δω 1 w At dt dt² w f t W; 2 Group 3 - Conversions (3.1) Sr.0 (3.2) Ut=r.w (3.3) ar.a (3.4) ac = v² = w2r

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a The apparatuss angular acceleration As stated First angular velocity i 0 since the device is no longer at rest f final angular velocity Time t 717 s... View the full answer