Find $\frac{2}{dt}$ it $y={\displaystyle \underset{0}{\overset{7}{}}}(9t^2-8t7)dt$

$($t point$)$

$18x-8$

$x^{2}7$

$\frac{9}{2}{x}^2-\frac{8}{3}{x}^3\frac{7}{4}x$

$9x^2-8x7$

$3x^3-4x^{2}7x$