Question: Find a suitable substitution to evaluate integral space x cubed over left parenthesis x to the power of 4 plus 3 right parenthesis squared space

Find a suitable substitution to evaluate integral space x cubed over left parenthesis x to the power of 4 plus 3 right parenthesis squared space d x, and evaluate the integral. Option A u equals left parenthesis x to the power of 4 plus 3 right parenthesis squared comma space minus fraction numerator 1 over denominator 4 x cubed end fraction plus space C Option B u equals x to the power of 4 plus 3 comma space minus fraction numerator 1 over denominator 4 x cubed end fraction plus space C Option C u equals x to the power of 4 comma space minus fraction numerator 1 over denominator 4 left parenthesis x to the power of 4 plus 3 right parenthesis end fraction plus space C Option D u equals x to the power of 4 space plus space 3 comma space minus fraction numerator 1 over denominator 4 left parenthesis x to the power of 4 plus 3 right parenthesis end fraction plus space C

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