Find an exact closed-form formula for the worst-case number of array element comparisons made by selection...
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Find an exact closed-form formula for the worst-case number of array element comparisons made by selection sort on arrays of size n. Do the same for the number of swaps. void selection_sort (vector<string> & V) { } int n V.size(); for (int s = n; s > 1; --s) { } = int mi(0); for (int i = 1; i < s; ++i) if (V[mi] < V[i]) i; mi = swap (V[mi], V[s-1]); Find an exact closed-form formula for the worst-case number of array element comparisons made by selection sort on arrays of size n. Do the same for the number of swaps. void selection_sort (vector<string> & V) { } int n V.size(); for (int s = n; s > 1; --s) { } = int mi(0); for (int i = 1; i < s; ++i) if (V[mi] < V[i]) i; mi = swap (V[mi], V[s-1]);
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Ans In worstcase scenario elements will be arranged in descending order ie largest element at index ... View the full answer
Related Book For
Data Structures and Algorithm Analysis in Java
ISBN: 978-0132576277
3rd edition
Authors: Mark A. Weiss
Posted Date:
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