Find $\frac{?}{\text{b}\text{a}\text{r}}(y)($the y$-$distance from the origin to the centroidal axis, $x^{\text{'}})$ and the moment of inertia of the cross$-$sectional area about $x^{\text{'}},$ given:

$L_1=130mm,L_2=180mm,L_3=40mm,L_4=55mm,L_5=30mm.$

$\frac{?}{\text{b}\text{a}\text{r}}(y)=$

$105$ mm

$44\mathrm{.}0$ mm

$59\mathrm{.}2$ mm

$33\mathrm{.}2$ mm

$76\mathrm{.}5$ mm

$I_{x^{\text{'}}}=$

$11\mathrm{.}3{10}^{6}m{m}^4$

$35\mathrm{.}6{10}^{6}m{m}^4$

$15\mathrm{.}0{10}^{6}m{m}^4$

$20\mathrm{.}1{10}^{6}m{m}^4$