Find $\frac{dz}{dt}$ using the chain rule where

$z=3x^2{y}^3,x=t^4,$ and $y=t^2.$

$\frac{dz}{dt}=,?$

$42t^{13}$

$6t^{10}+9t^{12}$

$6x{y}^3+9x^2{y}^2$

$x{y}^{3}dx+9x^2{y}^{2}d$