Question: Find E[Y(Y - 1) ] for a geometric random variable Y by finding dq 2 y=1 2 00 da 2 =1 y=1 E[Y(Y - 1)]

Find E[Y(Y - 1) ] for a geometric random variable Y

Find E[Y(Y - 1) ] for a geometric random variable Y by finding dq 2 y=1 2 00 da 2 =1 y=1 E[Y(Y - 1)] = Use this result to find the variance of Y. V(Y) = E[Y(Y - 1)] + E()) - [E()12 2 = + D K =

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