Find $f^{-1}(x)$ and identify the domain and range $of{f}^{-1}.As$ a check, show that $f(f^{-1}(x))=f^{-1}(f(x))=x.$

$f(x)=\frac{x+5}{x-6}$

$f^{-1}(x)=\frac{6x+5}{x-1}$

$(Typean$ exact answer, using radicals $as$ needed.$)$

What $is$ the domain $of{f}^{-1}?$

$(-,1)(1,)(Type$ your answer $in$ interval notation.$)$

What $is$ the range $of{f}^{-1}?$

$(-,6)(6,)(Type$ your answer $in$ interval notation.$)$

Does $f(f^{-1}(x))=f^{-1}(f(x))=x?$ Find the intermediate forms $off(f^{-1}(x))$ and $f^{-1}(f(x)).$

$f(f^{-1}(x))=x$ and $f^{-1}(f(x))=x$

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$xas$ the variable. $Do$ not simplify.