Find $f^{\text{'}}(a).$

$f(t)=\frac{6t+4}{t+8}$

To find $f^{\text{'}}(a),$ we will use the formula

$f^{\text{'}}(a)=\underset{ta}{lim}\frac{f(t)-f(a)}{t-a}$

Since $f(t)=\frac{6t+4}{t+8}$ we have

$f^{\text{'}}(a)=\underset{ta}{lim}\frac{\frac{6t+4}{t+8}-\frac{6a+4}{a+8}}{t-a}$

Simplifying everything we get

$f^{\text{'}}(a)=\underset{ta}{lim}|||=$

Find $f^{\text{'}}(a).$

$f(t)=\frac{6t+4}{t+8}$

To find $f^{\text{'}}(a),$ we will use the formula

$f^{\text{'}}(a)=\underset{ta}{lim}\frac{f(t)-f(a)}{t-a}$

Since $f(t)=\frac{6t+4}{t+8}$ we have

$f^{\text{'}}(a)=\underset{ta}{lim}\frac{\frac{6t+4}{t+8}-\frac{6a+4}{a+8}}{t-a}$

Simplifying everything we get

$f^{\text{'}}(a)=\underset{ta}{lim}|||=$