Question: Find i(t): v(t) = 120sin (377: + 60) V 1 = 12 = 2 Find i, (t) impedance: i(t) V = i(t) 1 WC

Find i(t): v(t) = 120sin (377: + 60) V 1 = 12

Find i(t): v(t) = 120sin (377: + 60) V 1 = 12 = 2 Find i, (t) impedance: i(t) V = i(t) 1 WC Phasor voltage (as cosine) V = 1202(60-90) = 120/(-30)* Find i,(t) impedance: 50F V 1204(-30) 254(37) wL = 377 40 10-3 = 15.08 = 53.05 It is (t) 2002 Z = R + jwL = 20+ j15.08 = 252(37)* ele = 40mH 120/(-30) 1202(-30)* -j53.05 53.052(-90) -= 4.84(-67)* A = 2.26260 A

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