Find pCa in a $100mL$ solution of $0\mathrm{.}10MC{a}^{2+}$ at $pH10$ after addition of $100mL$ of $0\mathrm{.}10$MEDTA. a$4$ at pH $10$ is $0\mathrm{.}35.kf=5{10}^{10}$

a$.1\mathrm{.}22$

b$.1$

C$.,5\mathrm{.}77$

d$.1\mathrm{.}48$