Find second partial derivatives $of$ the function $f(x,y,z)=2e^{xyz}at$ the point $x_0=(-1,-7,3).$

$(Use$ symbolic notation and fractions where needed.$)$

$f_{}(-1,-7,3)=$

Correct Answer

$f_{zz}(-1,-7,3)=$

Correct Answer

$f_{xz}(-1,-7,3)=$

$f_{yy}(-1,-7,3)=$

Correct Answer

$f_{xy}(-1,-7,3)=$

Incorrect Answer

$f_{yz}(-1,-7,3)=$

Correct Answer

Sorry, that's incorrect.

You have not correctly calculated all $of$ the partial derivatives $at$ the

given point.

Notice that part $of$ the exponential function does not change when taking $a$

derivative with respect $to$ any $of$ the variables.

Let's start with a hint:

Calculate the required partial derivatives and then plug $in{x}_0.$

Here are a few ways that I can help: