Question: Find solution:- fIt has been claimed that no more than 5% of the units coming off an assembly line are defective. Formulate a null hypothesis

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Find solution:- \fIt has been claimed that no more than 5% ofthe units coming off an assembly line are defective. Formulate a nullhypothesis and an alternative hypothesis for this situation. Will the test beone- tail or two-tail? Why? If the test is one-tail, will itbe left-tail or right-tail? Why?If the population standard deviation is known, butthe sample size is less than 30, what assumption is necessary touse the z-statistic in carrying out a hypothesis test for the populationForeach of the following tests and z values, determine the p-value forthe test: a. Right-tail test and z = 1.54 b. Left-tail testand z = -1.03 C. Two-tail test and z = -1.83For asample of 35 items from a population for which the standard deviationis o = 20.5, the sample mean is 458.0. At the 0.05level of significance, test H,: p = 450 versus H, : J= 450. Determine and interpret the p-value for the test.For a sampleof 12 items from a normally distributed population for which the standarddeviation is 5 17.0, the sample mean is 230.8. At the 0.05level of significance, test Hip $ 220 versus H, :y > 220.Determine and interpret the p-value for the test.image text in transcribed

\fIt has been claimed that no more than 5% of the units coming off an assembly line are defective. Formulate a null hypothesis and an alternative hypothesis for this situation. Will the test be one- tail or two-tail? Why? If the test is one-tail, will it be left-tail or right-tail? Why?If the population standard deviation is known, but the sample size is less than 30, what assumption is necessary to use the z-statistic in carrying out a hypothesis test for the populationFor each of the following tests and z values, determine the p-value for the test: a. Right-tail test and z = 1.54 b. Left-tail test and z = -1.03 C. Two-tail test and z = -1.83For a sample of 35 items from a population for which the standard deviation is o = 20.5, the sample mean is 458.0. At the 0.05 level of significance, test H,: p = 450 versus H, : J = 450. Determine and interpret the p-value for the test.For a sample of 12 items from a normally distributed population for which the standard deviation is 5 17.0, the sample mean is 230.8. At the 0.05 level of significance, test Hip $ 220 versus H, :y > 220. Determine and interpret the p-value for the test.

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