Find the area enclosed by the curve x = t - 3t, y = t and...

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Find the area enclosed by the curve x = t² - 3t, y = √t and the y-axis. Step 1 The curve x = t² - 3t, y = √√t intersects the y-axis when x = 0, which occurs when t = 0 and t = 3 Step 2 ✓ Using A = -3 - [ox dy = fº ry = √3 20 -2 (XR - XL) dy = f(t)g'(t) dt, where f(t) = 3t - Submit Skip (you cannot come back) y Jt = 0 == ft = 3 -6³ (1 X [0x(t)]y'(t) dt 3t-12 t² and g(t) = √t, the shaded area is given by: X )(2+/7) ot. Find the area enclosed by the curve x = t² - 3t, y = √t and the y-axis. Step 1 The curve x = t² - 3t, y = √√t intersects the y-axis when x = 0, which occurs when t = 0 and t = 3 Step 2 ✓ Using A = -3 - [ox dy = fº ry = √3 20 -2 (XR - XL) dy = f(t)g'(t) dt, where f(t) = 3t - Submit Skip (you cannot come back) y Jt = 0 == ft = 3 -6³ (1 X [0x(t)]y'(t) dt 3t-12 t² and g(t) = √t, the shaded area is given by: X )(2+/7) ot.

Answer rating: 100% (QA)

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