Find the area of the shaded region. A = -4 y = x (-2, 4)...

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● ● ● Find the area of the shaded region. A = ● -4 y = x² (-2, 4) -2 y 8 4 2 (1, 6) 3y=2x+16 2 The x y-coordinate plane is given. There is a curve, two lines, and a region on the graph. The curve labeled y = x² enters the window in the second quadrant, goes down and right becoming less steep, passes through the point (-2, 4) crossing the first line, changes direction at the origin, goes up and right becoming more steep, passes through the point (2, 4) crossing the second line, and exits the window in the first quadrant. The first line labeled 3y = 2x + 16 enters the window in the second quadrant, goes up and right, passes through the point (-2, 4) crossing the curve, crosses the y-axis at approximately y = 5.3, passes through the point (1, 6) crossing the second line, and exits the window in the first quadrant. (2, 4) y=8-2x 4 The second line labeled y = 8 - 2x enters the window in the second quadrant, goes down and right, crosses the y-axis at y = 8, passes through the point (1, 6) crossing the first line, passes through the point (2, 4) crossing the curve, crosses the x-axis at x = 4, and exits the window in the fourth quadrant. The region is above the curve and below the two lines. ● ● ● Find the area of the shaded region. A = ● -4 y = x² (-2, 4) -2 y 8 4 2 (1, 6) 3y=2x+16 2 The x y-coordinate plane is given. There is a curve, two lines, and a region on the graph. The curve labeled y = x² enters the window in the second quadrant, goes down and right becoming less steep, passes through the point (-2, 4) crossing the first line, changes direction at the origin, goes up and right becoming more steep, passes through the point (2, 4) crossing the second line, and exits the window in the first quadrant. The first line labeled 3y = 2x + 16 enters the window in the second quadrant, goes up and right, passes through the point (-2, 4) crossing the curve, crosses the y-axis at approximately y = 5.3, passes through the point (1, 6) crossing the second line, and exits the window in the first quadrant. (2, 4) y=8-2x 4 The second line labeled y = 8 - 2x enters the window in the second quadrant, goes down and right, crosses the y-axis at y = 8, passes through the point (1, 6) crossing the first line, passes through the point (2, 4) crossing the curve, crosses the x-axis at x = 4, and exits the window in the fourth quadrant. The region is above the curve and below the two lines.

Answer rating: 100% (QA)

Solution Area trangu X height 0 Area under Curve us... View the full answer