Question: Find the definite integral given that f(x) dx = 6, 8(x ) dx = -9, / 's(x)dx = 2, /' 8 (x )dx = 1


Find the definite integral given that f(x) dx = 6, 8(x ) dx = -9, / 's(x)dx = 2, /' 8 (x )dx = 1 (Give an exact answer. Use symbolic notation and fractions where needed.) [f (x) - g(x)] dx =
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