Find the derivative of the following function.

sequals$=$t Superscript $9$ Baseline ln StartAbsoluteValue t EndAbsoluteValuet$9$lnt

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Part $1$

Which rule of differentiation will be most helpful in beginning this$$ problem?

A$.$

The product rule

B$.$

The constant rule

C$.$

The sum or difference rule

D$.$

The power rule

E$.$

The chain rule

Part $2$

The expression

ln StartAbsoluteValue t EndAbsoluteValuelnt

appears as a subexpression of the given function. What is the derivative of this$$ expression?

StartFraction d Over dt EndFraction left parenthesis ln StartAbsoluteValue t EndAbsoluteValue right parenthesisddt$($lnt$)$equals$=$enter your response here

Part $3$

Find the derivative of the given function.

StartFraction ds Over dt EndFractiondsdtequals$=$enter your response here

$($Use parentheses to clearly denote the argument of each$$ function.$)$