Find the energy released when $16355$ undergoes decay to become $17$C$1.$ m$(1635)=34\mathrm{.}969033$u$,(173$ C$1)=34\mathrm{.}968853$u$,$ m$2*$He$)=4\mathrm{.}002603$u$,.=1\mathrm{.}007276,,=1008665$u$,$ m$.=5\mathrm{.}4875799$x$104$u$.$ Note that the mass of electrons is included in the mass of neutral atoms.