Find the equation for the line passing through $P=(-3,-3,1)$ and perpendicular to the plane $2x+y+3z=1.$ Note that the correct answer below can be either in parametric or symmetric form.

A$.\frac{x-3}{2}=\frac{y-3}{1}=\frac{z+1}{3}.$

B$.($:$-3+2t,-3+t,1+3t$:$)$

c$.($:$2+3t,1+3t,3-t$:$)$

D$.\frac{x-2}{-3}=\frac{y-1}{-3}=\frac{z-3}{1}$

E$.-3x-3y+z=-6$