Find the following by using the methods for evaluating limits $($i$.$e$.$ factoring, conjugate, etc.$).$

$i$

$ii$

iii$)\underset{x0}{lim}\frac{\frac{1}{x-7}+\frac{1}{7}}{x},""$

$=\underset{x0}{lim}\frac{(\frac{1}{x-7}+\frac{1}{7})}{x}*\frac{7(x-7)}{7(x-7)}$

$=\underset{x0}{lim}\frac{7+(x-7)}{7x(x-7)}$

$=\underset{x0}{lim}\frac{x}{7(x-7)}=\underset{x0}{lim}\frac{1}{7(x-7)}=\frac{1}{7(-7)}=\frac{1}{-42}$

Can you construct a problem similar $to$ this and explain how you did $itso$ that i may $be$ able $to$ solve $it?$