Find the general solution to the differential equation using the method of variation of parameters. y" + 4y = sec(2t) y(t) = ci cos(2t) + c2 sin(2t) + t cos(2t) - -In | sec(2t) | sin(2t) 1 y(t) = ci cos(2t) + co sin(2t) + 2t sin(2t) - In | sec(2t) | cos(2t) y(t) = ci cos(2t) + c2 sin(2t) + t cos(2t) - - In | sec(2t) | sin(2t) 1 O y(t) = c1 cos(2t) + c2 sin(2t) 1 y(t) = ci cos(2t) + 2 sin(2t) + tsin(2t) - -In | sec(2t) | cos(2t)