Find the gradient of the function at the given point.

$f(x,y)=2x3y^{2}2,(1,2)$

gradf$(1,2)=$

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$13.[-/1$ Points$]$

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LARCALC$1213\mathrm{.}6\mathrm{.}026.$MI$.$

Use the gradient to find the directional derivative of the function at $P$ in the direction

$f(x,y)=3x^2-y^{2}4,P(-2,3),Q(5,8)$