Find the indefinite integral.

${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}16(x-2{)}^{7}dx$

Step $1$

To find the indefinite integral ${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}16(x-2{)}^{7}dx,$ first use the constant multiple rule.

${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}16(x-2{)}^{7}dx={\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}(x-2{)}^{7}dx$