Find the integral using an appropriate trigonometric substitution.

${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}\frac{\sqrt[\phantom{2}]{25x^2-4}}{x}dx$

which of the following is the correct substitution?

$x=\frac{2}{5}sin$

$x=\frac{5}{2}tan$

$x=\frac{2}{5}tan$

$x=\frac{5}{2}sec$

$x=\frac{2}{5}tsc$

$x=\frac{3}{2}sin$