Find the integral.

${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}\frac{\sqrt[\phantom{2}]{x}-1}{\sqrt[\phantom{2}]{x}}dx$

$x-2\sqrt[\phantom{2}]{x}C$

$\frac{\sqrt[\phantom{2}]{x}-1}{\sqrt[\phantom{2}]{x}}C$

$\frac{1}{2}(\sqrt[\phantom{2}]{x}-1{)}^{2}C$

$\sqrt[\phantom{2}]{x}-4c$