Find the inverse function, f$^-1($x$),$ for f$($x$)=(9-$x$^2),0$ x $3.[$ f$^-1($x$)=(9+$x$^2)$; f$^-1($x$)=3-$x; f$^-1($x$)=(9-$x$^2),0$ x $3$; f$^-1($x$)=(9-$x$^2),0$ x $3$; f$^-1($x$)=($x$^2-9),$ x $3]$