Find the Laplace transform $F(s)=L\{f(t)\}$ of the function $f(t)=(6-t)(h(t-4)-h(t-6)),$ for $s0.$

$F(s)=L\{f(t)\}=$

$-e^{-4s}(\frac{6}{s}-\frac{1}{s^2})-e^{-6s}(\frac{6}{s}-\frac{1}{s^2})$

help $($formulas$).$