Find the largest interval, I, in which a function $y(t)$ solution of the initial value problem

$y^{\text{'}\text{'}}\frac{t}{(t-1)}{y}^{\text{'}}(t1)y=\frac{1}{(t-3)}$

$y(-1)=1,y^{\text{'}}(-1)=4I=(2,4)$

$I=(0,)$

$I=(-,1)(1,3)(3,)$

$I=(-,0)$

$I=(-,)$

$I=(-,0)(0,1)(1,3)(3,)$

$I=(-,1)$

$I=(1,3)$

None of the options displayed.

$I=(3,)$