Find the limit $L.$

$L=$

Use the $-$ definition to prove that the limit is $L.$

Given $>0,$ assume then

Assuming

$|\sqrt[\phantom{2}]{x}-()|<mi></mi>$

you can choose $=7.$ Then,

when $=7,$ you have

$|x-()|<mi></mi><mi>|</mi><mroot><mrow><mi>x</mi><mspace\; width="thinmathspace"></mspace></mrow><mrow><mphantom><mn>2</mn></mphantom></mrow></mroot><mtext></mtext><mn>4</mn><mi>|</mi>$

$|\sqrt[\phantom{2}]{x}-()|<mi></mi>$

$|f(x)-L|<mi></mi>$