Find the linearization $L(x)$ of the function at a$.$

$f(x)=x^3-x^{2}4,a=-2$

Step $1$

Recall that the linearization of $f(x)$ for $x=a$ is given by

$L(x)=f(a)f^{\text{'}}(a)(x-a)$

For $f(x)=x^3-x^{2}4,$ we have the following.

$P(x)=$

Step $2$

Now, at $a=-2,$ we have $f(-2)=$ and $f^{\text{'}\text{'}}(-2)=$