Find the linearization L$($x$)$ of the function at a$.$

f$($x$)=$x$^(3)-$x$^(2)+8,$a$=-3$

Step $1$

Recall that the linearization of f$($x$)$ for x$=$a is given by

L$($x$)=$f$($a$)+$f$^(\text{'})($a$)($x$-$a$).$

For f$($x$)=$x$^(3)-$x$^(2)+8,$ we have the following.

f$^(\text{'})($x$)=$

Step $2$

Now, at a$=-3,$ we have f$(-3)=$

and f$^(\text{'})(-3)=$

SKIP $($YOU CANNOT COME BACK$)$