Find the Maclaurin series $of$ the function.

$f(x)=ln(1-5x)$

Choose the Maclaurin series.

$ln(1-5x)={\displaystyle \underset{n=1}{\overset{}{}}}\frac{(-1{)}^{n-1}{5}^n{x}^n}{n}$

$ln(1-5x)=-{\displaystyle \underset{n=1}{\overset{}{}}}\frac{5^n{x}^n}{5n}$

$ln(1-5x)=-{\displaystyle \underset{n=1}{\overset{}{}}}\frac{5^n{x}^n}{n}$

$ln(1-5x)={\displaystyle \underset{n=1}{\overset{}{}}}\frac{(-1{)}^{n-1}{x}^{5n}}{5n}$ for infinity, $U$ for combining intervals, and $an$ appropriate

type $of$ parenthesis $"(",")","[","]"$ depending $on$ whether the interval $is$ open $or$ closed. Enter $\frac{O}{?}if$ the interval $is$ empty. Express

numbers $in$ exact form. Use symbolic notation and fractions where needed.