Find the most general antiderivative.

${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}(\frac{1}{x^5}-x^5-\frac{1}{9})dx$

A$.\frac{1}{5x^6}-\frac{x^6}{6}-\frac{1}{9x}C$

B$.-5x^4-5x^{5}C$

c$.-\frac{1}{4x^4}-\frac{x^6}{6}-\frac{x}{9}C$

D$.\frac{1}{6x^6}-\frac{x^4}{4}\frac{1}{81}c$