Find the open intervals where the function is concave upward or concave downward. Find any inflection points. f(x) = - 4x5 +30x2 + 175x -7 Where is the function concave upward and where is it concave downward? Select the correct choice below and, if necessary, fill in the answer box(es) to complete your choice. O A. The function is concave upward on the interval(s) and concave downward on the interval(s) (Type your answers in interval notation. Use integers or fractions for any numbers in the expressions. Use a comma to separate answers as needed.) O B. The function is concave upward on the interval(s) . The function is never concave downward. (Type your answer in interval notation. Use integers or fractions for any numbers in the expression. Use a comma to separate answers as needed.) C. The function is concave downward on the interval(s) . The function is never concave upward. (Type your answer in interval notation. Use integers or fractions for any numbers in the expression. Use a comma to separate answers as needed.) O D. The function is never concave upward or downward. Find any inflection points of f. Select the correct choice below and, if necessary, fill in the answer box to complete your choice. O A. The function has an inflection point at (Type an ordered pair, using integers or fractions. Use a comma to separate answers as needed. ) O B. The function f has no inflection points.5x x2+1 The percent of concentration of a certain drug in the bloodstream x hours after the drug is administered is given by K(x) = a. Find the time at which the concentration is a maximum. b. Find the maximum concentration. a. The concentration will be maximized at x = hour(s). b. The maximum concentration is |:%. If a cannonball is shot directly upward with a velocity of 176 ft per second, its height above the ground after t seconds is given by s(t) = 176t - 16t. Find the velocity and the acceleration after t seconds. What is the maximum height the cannonball reaches? When does it hit the ground? The velocity after t seconds is v(t) = |ft/sec. The acceleration after t seconds is a(t) = ft/sec2. The cannonball reaches a maximum height of ft. The cannonball hits the ground after t= sec