Find the point of intersection between the line:

x$=2+3$t$,$y$=9+4$t$,$z$=1+10$tx $=-2+3$t$,\backslash$quad y $=9+4$t$,\backslash$quad z $=1+10$tx$=2+3$t$,$y$=9+4$t$,$z$=1+10$t

and the plane:

$8$x$+3$y$+6$z$=5\mathrm{.}8$x $+3$y $+6$z $=5\mathrm{.}8$x$+3$y$+6$z$=5.$

Answer choices:

a$)(138,72,94)\backslash$left$(\backslash$frac$\{-13\}\{8\},\backslash$frac$\{7\}\{2\},\backslash$frac$\{9\}\{4\}\backslash$right$)(813,27,49)$

b$)(1,13,11)(1,13,11)(1,13,11)$

c$)(198,172,14)\backslash$left$(\backslash$frac$\{-19\}\{8\},\backslash$frac$\{17\}\{2\},\backslash$frac$\{-1\}\{4\}\backslash$right$)(819,217,41)$

d$)(5,5,9)(-5,5,9)(5,5,9)$