Find the present value $P(in$ dollars$)of$ a continuous income flow $ofc(t)$ dollars per year using

$P={\displaystyle \underset{0}{\overset{t_1}{}}}c(t)e^{-rt}dt$

where $t_{1}is$ the time $in$ years and $ris$ the annual interest rate compounded continuously. $(Round$ your answer $to$ the nearest dollar.$)$

$c(t)=100,000+4,000t,r=5\%,t_1=8$

$

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