Find the probability that one customer is in the regular checkout line. Find the probability that no more than one customer is in line. Find the probability that at least two people are in line Find the probability that three or fewer customers are in line. What is the probability that no one is waiting or being served in the regular checkout line? What is the probability that at most one person is waiting or being served in the express checkout line? What is the probability that three customers are waiting in line? On average, how many customers would you expect to see in line? Find the probability that one customer is in the regular checkout line. P (X = 1) = 0.22 Find the probability that no more than one customer is in line. P (X 1) = P (X = 0) + P (X = 1) = 0.28 + 0.22 = 0.50 Find the probability that at least two people are in line P (X 2) = P (X = 2) + P (X = 3) = 0.26 + 0.24 = 0.50 Find the probability that three or fewer customers are in line. P (X 3) = P (X = 0) + P (X = 1) + P (X = 2) + P (X = 3) = 0.28 + 0.22 + 0.26 + 0.24 = 1.00 What is the probability that no one is waiting or being served in the regular checkout line? P (X = 0) = 0.28 What is the probability that at most one person is waiting or being served in the express checkout line? P (X 1) = P (X = 0) + P (X = 1) = 0.28 + 0.22 = 0.50 What is the probability that three customers are waiting in line? P (X = 0) = 0.24 On average, how many customers would you expect to see in line? E ( X )= xP ( X=x )=0 0.28+1 0.22+2 0.26+3 0.2 4 0+0.22+0. 5 2+0.72 1.46 Find the probability that one customer is in the regular checkout line. P (X = 1) = 0.22 Find the probability that no more than one customer is in line. P (X 1) = P (X = 0) + P (X = 1) = 0.28 + 0.22 = 0.50 Find the probability that at least two people are in line P (X 2) = P (X = 2) + P (X = 3) = 0.26 + 0.24 = 0.50 Find the probability that three or fewer customers are in line. P (X 3) = P (X = 0) + P (X = 1) + P (X = 2) + P (X = 3) = 0.28 + 0.22 + 0.26 + 0.24 = 1.00 What is the probability that no one is waiting or being served in the regular checkout line? P (X = 0) = 0.28 What is the probability that at most one person is waiting or being served in the express checkout line? P (X 1) = P (X = 0) + P (X = 1) = 0.28 + 0.22 = 0.50 What is the probability that three customers are waiting in line? P (X = 0) = 0.24 On average, how many customers would you expect to see in line? () = ( = ) = . + . + . + . = + . + . + . =