Find the solution to the given differential equation.

$y^{\text{'}}=\frac{2x}{y}$

$xdx+ydy=0$

$y^{\text{'}}=y(e^x+2)$

$3(y+2)dx-xdy=0$

$sinxsinydx+cosxcosydy=0$

$h^{}=15-16h$

$xydy+e^y(x-5)dx=0$

$y^{\text{'}}=sin(x+y)$