Question: Find the work done a particle once around the circle by x^2 + y^2 = a^2, z=6 in the force field F = (xy

Find the work done a particle once around the circle by x^2

Find the work done a particle once around the circle by x^2 + y^2 = a^2, z=6 in the force field F = (xy + sin(xy))t + (1/2x^2+ x/y Sin(xy) + 1/y^2 Cos(xy)] j + (e^x Cos(xy))k.

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