Question: Find the work done by the vector field F = 3 + 2 xy 2 , 2 x 2 y vec { F }

Find the work done by the vector field
F=3+2xy2,2x2y\vec{F}=\langle 3+2xy^2,\2x^2y \rangleF=3+2xy2,2x2y
to move a particle along the arc of the hyperbola y=1xy =\frac{1}{x}y=x1 from (1,1)(1,1)(1,1) to (4,14)(4,\frac{1}{4})(4,41).

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