Find $x_{194}$ given that $$ \begin{array}{1} x_{0}=1.75 11 X_{1}=.25 1 x_{n}=\frac{1}{6} \frac{\ln \left(4+x_{(n-1)} ight)}{x_{(n-2)}} \end{array} $$ and enter your answer correct to 10 significant figures in the box below. To check that your calculations are correct, you should be able to calculate that $x_{69}$ is approximately $1.476198$. [Note that you should do your calculations correct to 10 significant figures. Use Digits : $=10 ;$ ] CS. JG. 004