finish the code in c$++$:

$//$ TODO$2$

void normalize$\_$variables$($float variable$\_$array$[],$ const float variable$\_$means$[],$ const float variable$\_$stds$[],$ int length$)\{$

$//-------------------------------------------------------$

$//$ This function normalizes the values in the variable$\_$array using the provided means and standard deviations.

$//$

$//$ Inputs:

$//-$ variable$\_$array: a $1$D array of size 'length' containing the variables to be normalized.

$//-$ variable$\_$means: a $1$D array of size 'length' containing the mean values for each corresponding variable.

$//-$ variable$\_$stds: a $1$D array of size 'length' containing the standard deviations for each corresponding variable.

$//-$ length: an integer representing the number of elements in the variable$\_$array, variable$\_$means, and variable$\_$stds$.$

$//$

$//$ Outputs $($via argument$)$:

$//-$ The function modifies variable$\_$array in place. Each element is normalized by subtracting its mean and dividing by its standard deviation.

$//$

$//$ Functionality:

$//-$ For each element in variable$\_$array, the function performs the following normalization:

$//$ normalizedValue$\_$i $=($originalValue$\_$i $-$ mean$\_$i$)/$ standardDeviation$\_$i$.$

$//$

$//$ Example:

$//$ If variable$\_$array $=\{10,20,30\},$ variable$\_$means $=\{5,15,25\},$ and variable$\_$stds $=\{2,5,10\},$

$//-$ The function will compute:

$//$ The element $0$ of variable$\_$array $=(10-5)/2=2\mathrm{.}5,$

$//$ The element $1$ of variable$\_$array $=(20-15)/5=1,$

$//$ The element $2$ of variable$\_$array $=(30-25)/10=0\mathrm{.}5.$

$//$

$//**$ Your TODO: Implement this function. $**$

$\}$